怎么把数组的值变成健名形成新的数组

如何把数组的值变成健名形成新的数组。
本帖最后由 xuexi123abc163 于 2014-11-24 11:40:57 编辑

(
[0] => Array
(
[ak] => 1
[fs] => 12
[tss] => sd第三方f
)

[1] => Array
(
[ak] => 2
[fs] => 12
[tss] => 是的发生
)

[2] => Array
(
[ak] => 3
[fs] => 22
[tss] => 好新玩
)

[3] => Array
(
[ak] => 4
[fs] => 22
[tss] => 八实得分
)
[4] => Array
(
[ak] => 6
[fs] => 22
[tss] => 八实得分
)
)

上面的数组是$abc
我下奶想形成新的数组把fs的值作为键名，然后把fs的值相同的，形成新的数组，。。

数组如下：

(
[12] => Array
(
[0] => Array
(
[ak] => 2
[tss] => 是的发生
)
[1] => Array
(
[ak] => 2
[tss] => 是的发生
)
)

[22] => Array
(
...............
)
)





------解决思路----------------------

$ar = array (
  array (
    'ak' => '1',
    'fs' => '12',
    'tss' => 'sd第三方f',
  ),
  array (
    'ak' => '2',
    'fs' => '12',
    'tss' => '是的发生',
  ),
  array (
    'ak' => '3',
    'fs' => '22',
    'tss' => '好新玩',
  ),
  array (
    'ak' => '4',
    'fs' => '22',
    'tss' => '八实得分',
  ),
  array (
    'ak' => '6',
    'fs' => '22',
    'tss' => '八实得分',
  ),
);
$res = array();
foreach($ar as $r) {
  $t = $r['fs'];
  unset($r['fs']);
  $res[$t][] = $r;
}
print_r($res);

Array
(
    [12] => Array
        (
            [0] => Array
                (
                    [ak] => 1
                    [tss] => sd第三方f
                )

            [1] => Array
                (
                    [ak] => 2
                    [tss] => 是的发生
                )

        )

    [22] => Array
        (
            [0] => Array
                (
                    [ak] => 3
                    [tss] => 好新玩
                )

            [1] => Array
                (
                    [ak] => 4
                    [tss] => 八实得分
                )

            [2] => Array
                (
                    [ak] => 6
                    [tss] => 八实得分
                )

        )

)