这段代码中echo如何不执行呢，高手给支个招

这段代码中echo怎么不执行呢，高手给支个招
本帖最后由 xuzuning 于 2014-07-01 17:05:54 编辑

public function add(){
		$this->lottory_record_db=M('Lottery_record');
		$this->lottory_db=M('Lottery');
		 if($_POST['action'] ==  'add' ){
			$lid 				= $this->_post('lid');
			$wechaid 			= $this->_post('wechaid');
			//$data['sn']			= $this->_post('sncode');
			$data['phone'] 		= $this->_post('tel');
			//$data['prize']		= $this->_post('winprize');
			$data['wecha_name'] = $this->_post('wxname');
			//$data['time']		= time(); 
			//$data['islottery']	= 1;
			//$data['usenums']	= 1;			
			$rid=intval($this->_post('rid'));
			if (!$rid){
				$thisRecord=$this->lottory_record_db->where(array('lid'=>$lid,'wecha_id'=>$wechaid,'islottery'=>1))->find();
				$rid=$thisRecord['id'];
			}
			$rollback = $this->lottory_record_db->where(array('lid'=>$lid,'wecha_id'=>$wechaid,'id'=>$rid))->save($data);
			$record=$this->lottory_record_db->where(array('id'=>$rid))->find();
			echo'{"success":1,"msg":"恭喜！尊敬的'.$data['wecha_name'].'请您保持手机通畅！你的领奖序号:'.$record['sn'].'"}';
			exit;	
		}
	}

------解决方案--------------------
if($_POST['action'] == 'add' ){
条件 $_POST['action'] == 'add' 不成立，所以 echo 不执行
------解决方案--------------------

var_dump($_POST['action']);//

输出看看值是什么？确定条件成立？


------解决方案--------------------
var_dump($_POST['action']);
------解决方案--------------------
那你输出的只是一个 json 串，需要 js 代码去解析呀