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数组计算差值及项的小计,该如何处理

时间:2021-07-01 10:21:17 帮助过:4人阅读

数组计算差值及项的小计
本帖最后由 lazygc520 于 2014-04-14 16:19:41 编辑

$s = array ( 0 => array ( 0 => array ( 0 => '2014-04-11', 'time' => '2014-04-11', 1 => 'BEA01-120N', 'type' => 'BEA01-120N', 2 => 176, 'count' => 176, ), 1 => array ( 0 => '2014-04-11', 'time' => '2014-04-11', 1 => 'BEA21-110N', 'type' => 'BEA21-110N', 2 => 1056, 'count' => 1056, ), ), 1 => array ( 0 => array ( 0 => '2014-04-11', 'time' => '2014-04-11', 1 => 'BEA01-120N', 'type' => 'BEA01-120N', 2 => 192, 'count' => 192, ), 1 => array ( 0 => '2014-04-11', 'time' => '2014-04-11', 1 => 'BEA21-110N', 'type' => 'BEA21-110N', 2 => 960, 'count' => 960, ), ), )

求其type对应的差值和$s[0]及$s[1]的type项的小计。(小计部分已实现,用了unset)


理想得到的结果:

小计的结果: BEA01-120N 176 BEA01-120N 192 差值:176-192 = -16
BEA21-110N 1056 BEA21-110N 960 1056-960 = 96
小计:176+1056=1232 192+960 = 1152
------解决方案--------------------
$s = array (
0 => array (
0 => array (
0 => '2014-04-11', 'time' => '2014-04-11',
1 => 'BEA01-120N', 'type' => 'BEA01-120N',
2 => 176, 'count' => 176,
),
1 => array (
0 => '2014-04-11', 'time' => '2014-04-11',
1 => 'BEA21-110N', 'type' => 'BEA21-110N',
2 => 1056, 'count' => 1056,
),
),
1 => array (
0 => array (
0 => '2014-04-11', 'time' => '2014-04-11',
1 => 'BEA01-120N', 'type' => 'BEA01-120N',
2 => 192, 'count' => 192,
),
1 => array (
0 => '2014-04-11', 'time' => '2014-04-11',
1 => 'BEA21-110N', 'type' => 'BEA21-110N',
2 => 960, 'count' => 960,
),
),
);

function foo($a, $b) {
for($i=0; $i $res[] = array($a[$i]['type'], $a[$i]['count'] - $b[$i]['count']);
}
return $res;
}

$t = call_user_func_array('foo', $s);
print_r($t);
Array
(
[0] => Array
(
[0] => BEA01-120N
[1] => -16
)

[1] => Array
(
[0] => BEA21-110N
[1] => 96
)

)

小计你已经做了,我就偷懒了
------解决方案--------------------
$s = array (
0 => array (
0 => array (
0 => '2014-04-11', 'time' => '2014-04-11',
1 => 'BEA01-120N', 'type' => 'BEA01-120N',
2 => 176, 'count' => 176,
),

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