当前位置:Gxlcms > PHP教程 > json对象的变换,新手求大神帮忙

json对象的变换,新手求大神帮忙

时间:2021-07-01 10:21:17 帮助过:41人阅读

json对象的转换,新手求大神帮忙
json格式如下
{"loginResult":{"code":"005","teamId":"1","password":"123","role":"员工","roleId":"2"}}

我用的CI框架 在models 里面定义了一个Member_Model对象,属性有code,teamId,password,role,roleId
怎样将上面的JSON数据转换成对象赋给Member_Model


------解决方案--------------------
$json = '{"loginResult":{"code":"005","teamId":"1","password":"123","role":"员工","roleId":"2"}}';
$arr = json_decode($json);
$mm = new Member_Model();
foreach ($arr->loginResult as $key => $value) {
$mm->$key = $value;
}

------解决方案--------------------
$s='{"loginResult":{"code":"005","teamId":"1","password":"123","role":"员工","roleId":"2"}}';
$o = json_decode($s);
print_r($o->loginResult);

------解决方案--------------------
如果是
$result = json_decode($buffer, true);

$member = $result['loginResult'];

如果是
$result = json_decode($buffer);

$member = $result->loginResult;

人气教程排行