求个地址获取的代码详细请见帖子解决方案

求个地址获取的代码详细请见帖子
比如土豆的视频地址为：http://www.tudou.com/a/OpofdZOE_mI/&iid=131686432&resourceId=0_04_05_99/v.swf
直接访问后为：
http://js.tudouui.com/bin/player2/olc_8.swf?iid=131686432&swfPath=http://js.tudouui.com/bin/lingtong/SocialPlayer_79.swf&youkuId=XNjc0MTE5MDky&vcode=XNjc0MTE5MDky&tvcCode=-1&tag=null&title=%E7%AC%AC07%E8%AF%9D+%E8%80%8D%E9%98%B4%E9%99%A9%E2%80%A6%E2%80%A6%21%21&mediaType=vi&totalTime=1434760&hdType=3&hasPassword=0&nWidth=512&isOriginal=0&channelId=9&nHeight=288&banPublic=false&videoOwner=102599789&tict=2&tvcCode=-1&channelId=9&cs=6_480|482&k=&totalTime=1434760&panelRecm=http://css.tudouui.com/bin/lingtong/PanelRecm_9.swz&panelDanmu=http://css.tudouui.com/bin/lingtong/PanelDanmu_1.swz&panelEnd=http://css.tudouui.com/bin/lingtong/PanelEnd_11.swz&pepper=http://css.tudouui.com/bin/binder/pepper_17.png&panelShare=http://css.tudouui.com/bin/lingtong/PanelShare_7.swz&panelCloud=http://css.tudouui.com/bin/lingtong/PanelCloud_8.swz&prd=&autoPlay=false&listType=3&rurl=&resourceId=0_04_05_99&autostart=false&lid=0&aid=228258&aCode=OpofdZOE_mI&code=JH-1K_odtwE&snap_pic=http%3A%2F%2Fr1.ykimg.com%2F054104085301E3696A0A4F52041D537C&aopRate=0.001&p2pRate=0.95&adSourceId=81000&yjuid=1392279724827k3i&yseid=1392887009649TQcVcx&yseidtimeout=1392898462767&yseidcount=4&uid=null&juid=018h4v26uu19ca&vip=0
怎么样用PHP获取访问后的地址并输出
------解决方案--------------------

$url='http://www.tudou.com/a/OpofdZOE_mI/&iid=131686432&resourceId=0_04_05_99/v.swf';
$ch = curl_init($url);
curl_setopt($ch, CURLOPT_FOLLOWLOCATION, false);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_HEADER, true);
curl_exec($ch);

$response = curl_exec($ch);

preg_match_all('/^Location:(.*)$/mi', $response, $matches);
curl_close($ch);

echo !empty($matches[1]) ? trim($matches[1][0]) : 'No redirect found';