输出数组给js用的有关问题

输出数组给js用的问题

 data = [{

y: 100,

color: colors[0],

drilldown: {

name: 'MSIE versions',

categories: ['MSIE 6.0', 'MSIE 7.0', 'MSIE 8.0', 'MSIE 9.0'],

data: [10.85, 7.35, 33.06, 2.81],

color: colors[0]

}

}, {

y: 21.63,

color: colors[1],

drilldown: {

name: 'Firefox versions',

categories: ['Firefox 2.0', 'Firefox 3.0', 'Firefox 3.5', 'Firefox 3.6', 'Firefox 4.0'],

data: [0.20, 0.83, 1.58, 13.12, 5.43],

color: colors[1]

}

}, {

y: 11.94,

color: colors[2],

drilldown: {

name: 'Chrome versions',

categories: ['Chrome 5.0', 'Chrome 6.0', 'Chrome 7.0', 'Chrome 8.0', 'Chrome 9.0',

'Chrome 10.0', 'Chrome 11.0', 'Chrome 12.0'],

data: [0.12, 0.19, 0.12, 0.36, 0.32, 9.91, 0.50, 0.22],

color: colors[2]

}

}, {

y: 7.15,

color: colors[3],

drilldown: {

name: 'Safari versions',

categories: ['Safari 5.0', 'Safari 4.0', 'Safari Win 5.0', 'Safari 4.1', 'Safari/Maxthon',

'Safari 3.1', 'Safari 4.1'],

data: [4.55, 1.42, 0.23, 0.21, 0.20, 0.19, 0.14],

color: colors[3]

}

}, {

y: 2.14,

color: colors[4],

drilldown: {

name: 'Opera versions',

categories: ['Opera 9.x', 'Opera 10.x', 'Opera 11.x'],

data: [ 0.12, 0.37, 1.65],

color: colors[4]

}

}]; 

以上是javascript原本的数组

data = [{"y":673,"color":"colors[0]","drilldown":{"name":"AMZ_AC \u660e\u7ec6","categories":["DE","ES","FR","GB","IT"],"data":["28","2","410","211","22"],"color":"colors[0]"}},{"y":290,"color":"colors[1]","drilldown":{"name":"AM_AC \u660e\u7ec6","categories":["JP"],"data":["290"],"color":"colors[1]"}},{"y":222,"color":"colors[2]","drilldown":{"name":"CO_AC \u660e\u7ec6","categories":["JP"],"data":["222"],"color":"colors[2]"}}];

以上是我用PHP输出的数组

请问这两个哪里不一样啊？？输出产生的结果跟原来的结果差好远

分享到：

------解决方案--------------------
是的，preg_replace是属于比较暴力的方法
但是你的 colors 是 js 的数组，php 又不可能知道。只能当做字符串处理了