批改信息成功后内容未变

修改信息成功后内容未变
系统有4处错误提示，分别在第15、17、25、26行。Undefined variable number1（PS：我发现我一个月都在问这个问题……惭愧）

   include "conn.php";

   include "admin_header.php";

   extract($_REQUEST);

  

   $query="update $jiaoshi_table set     subject='$newsubject',teacher='$newteacher',zhicheng='$newzhicheng',specialized='$newspecialized',code='$newcode',intrduction='newintroduction' where id='$id'";

   mysql_query("set names 'GB2312'");

   $result=mysql_query($query);

   

   

   $query="select number as sn,surplus as ssn from $jiaoshi_table where id='$id'";

   mysql_query("set names 'GB2312'");

   $result=mysql_query($query);

   $row=mysql_fetch_array($result);

		if($number1<$row['sn'])

		{

			if($number1<($row['sn']-$row['ssn']))

			{

				echo"
人数不能少于现已选题人数，人数列修改失败！";

				echo"";

				exit;

			}

			else

			{

		    	$query2=mysql_query("update $jiaoshi_table set number='$number1' where id='$id'");

				$query3=mysql_query("update $jiaoshi_table set surplus=surplus-($row[sn]-$number1) where id='$id'");

				mysql_query("set names 'GB2312'");

   				$result1=mysql_query($query3);

			}

		}

		else

		{

			$query4=mysql_query("update $jiaoshi_table set number='$number1' where id='$id'");

			$query5=mysql_query("update $jiaoshi_table set surplus=surplus+($number1-$row[sn]) where id='$id'");

			mysql_query("set names 'gb2312'");

   			$result2=mysql_query($query5);

   		}

		if($result==true)

				{

				   echo"
修改课题成功！";

				   echo "";

				   exit;

				 }

				 else

				 {

				   echo"
修改出错，请返回重新修改
";

				   echo ""; 

				   exit;

				 }

		

?>

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------解决方案--------------------
$number1 这个变量没值嘛，$number1是从哪取的值呀。