数组求和操作,该怎么处理

数组求和操作

foreach($a as $k=>$v)

{

	print_r($newarr);

	echo $a[$k]['5'].'
';

}

Array

(

    [0] => Array

        (

            [lotno] => 3206

            [count] => 12

        )



    [1] => Array

        (

            [lotno] => 3207

            [count] => 63

        )



    [2] => Array

        (

            [lotno] => 3218

            [count] => 180

        )



)

120

Array

(

    [0] => Array

        (

            [lotno] => 3206

            [count] => 12

        )



    [1] => Array

        (

            [lotno] => 3207

            [count] => 63

        )



    [2] => Array

        (

            [lotno] => 3218

            [count] => 180

        )



)

135

将count相加，如果对应行的结果为120，则显示3206*12 3207*63 3218*45
若对应行的结果为135，则显示3218*135 (135=180-45(上一轮count已用的45)，不够则补齐)

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------解决方案--------------------
这个意思

$ar = array (

	array( 'lotno' => 3206, 'count' => 12 ),

	array( 'lotno' => 3207, 'count' => 63 ),

	array( 'lotno' => 3218, 'count' => 180 ),

);



$s = '';

$n = 0;

foreach($ar as $r) {

  if($n + $r['count'] > 120) {

    echo $s . $r['lotno'] . '*' . (120-$n) ."\n";

    echo $r['lotno'] . '*' . ($n = $r['count'] - (120-$n)) ."\n";