怎么把一个列表中选项的值传到下个php界面中 if($roomID!=null)
{
$result=mysql_query("SELECT roomID,roomtype,roomsize FROM room WHERE roomID NOT IN (SELECT roomID FROM bookingroom WHERE bookingdate='$bookingdate' AND bookingtime='$bookingtime') AND roomID='$roomID'");
$num_rows = mysql_num_rows($result);
if ($num_rows==0) {
echo "