mysql怎么按特定id排序

mysql如何按特定id排序
mysql如何按特定id排序

SET FOREIGN_KEY_CHECKS=0;



-- ----------------------------

-- Table structure for `p`

-- ----------------------------

DROP TABLE IF EXISTS `p`;

CREATE TABLE `p` (

  `id` int(11) NOT NULL auto_increment,

  `name` varchar(255) default NULL,

  `categories_id` int(11) default NULL,

  PRIMARY KEY  (`id`)

) ENGINE=MyISAM AUTO_INCREMENT=7 DEFAULT CHARSET=utf8;



-- ----------------------------

-- Records of p

-- ----------------------------

INSERT INTO `p` VALUES ('1', 'jimmy', '2');

INSERT INTO `p` VALUES ('2', 'tina', '2');

INSERT INTO `p` VALUES ('3', 'dd', '2');

INSERT INTO `p` VALUES ('4', 'hello', '2');

INSERT INTO `p` VALUES ('5', 'world', '2');

INSERT INTO `p` VALUES ('6', 'slucky', '2');





SET FOREIGN_KEY_CHECKS=0;



-- ----------------------------

-- Table structure for `p_sort`

-- ----------------------------

DROP TABLE IF EXISTS `p_sort`;

CREATE TABLE `p_sort` (

  `categories_id` int(10) NOT NULL default '0',

  `best_sort_person_id` varchar(100) default NULL,

  PRIMARY KEY  (`categories_id`)

) ENGINE=MyISAM DEFAULT CHARSET=utf8;



-- ----------------------------

-- Records of p_sort

-- ----------------------------

INSERT INTO `p_sort` VALUES ('2', '2,5,1');

------解决方案--------------------

select * from p, p_sort

  order by find_in_set(p.id, p_sort.best_sort_person_id)>0 desc, find_in_set(p.id, p_sort.best_sort_person_id) asc, id 

find_in_set(p.id, p_sort.best_sort_person_id)>0 desc 用于将id=2,5,1的排在前面
find_in_set(p.id, p_sort.best_sort_person_id) asc 用于将id=2,5,1的按出现次序排列