时间:2021-07-01 10:21:17 帮助过:5人阅读
$row = 1; $handle = fopen("test.csv","r"); while ($data = fgetcsv($handle, 1000, ",")) { $num = count($data); echo "$num fields in line $row:
\n"; $row++; for ($c=0; $c < $num; $c++) { echo $data[$c] . "
\n"; } } fclose($handle); #我用上面的代码获取 #date #2011-4-21 #的数据能正常获取 #你的问题怎么解决的?