找出重复数据来,函数改写,该怎么解决

$array = array('1 23 234', '2 24 235', '3 24 235', '4 25 235', '5 25 235', '6 37 456', '7 37 456');
$newArray = array();
foreach ($array as $value) {
    preg_match('/^[0-9]+\s([0-9]+\s[0-9]+$)/', $value, $mArray);
    $newArray[] = $mArray[1];
}
$countArray = array_count_values($newArray);
$fixArray = array();

$i = 1;
foreach ($newArray as $newkey => &$value) {
    $newArrayKey = array();
    if (array_key_exists($value, array_flip($newArray))) {
        $newArrayKey = array_keys($newArray, $value);
        if (count($newArrayKey) !== 1) {
            $tmp = array_search($newkey, $newArrayKey);
            $tmp = intval($tmp) + 1;
            $fixArray[] = $i . ' ' . $value . '-' . $tmp . '/' . $countArray[$value];
        } else {
            $fixArray[] = $i . ' ' . $value;
        }
        $i++;
    }

}
print_r($fixArray);

------解决方案--------------------

妞妞，哪有事情做到一半的到底。起码也要注释解释一下吧。。

话说大版已好久没现身了。挺想念的。。