高分解难题：PHP查询MYSQL数据，记录集怎么特殊显示

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$result=mysql_query("select year(addtime) as y,group_concat(jiage) as str from table_name group by year(addtime);");
while($row=mysql_fetch_assoc($result)){
      echo '';
      echo "$row[y]";
      foreach(explode(',',$row[str]) as $v)
            echo "$v;
      echo '';
}
............
<br><font color="#e78608">------解决方案--------------------</font><br>
$result=mysql_query("select year(add_date) as y,group_concat(yc_jiage) as str from jiagedata group by year(add_date);") or die(mysql_error());<br><br>贴出提示。
<br><font color="#e78608">------解决方案--------------------</font><br>执行#12楼后提示什么信息。