时间:2021-07-01 10:21:17 帮助过:26人阅读
例如:我想添加一篇博客,里面有一个分类,我应该有一个category_id字段,然后在添加博客的时候可以通过下拉列表选择。
疑问:
我的下拉列表中怎么才能有我添加好的分类列表呢!
posts和category的关系
#Demo\TestBundle\Entity\Posts
Demo\TestBundle\Entity\Posts:
type: entity
table: posts
repositoryClass: Demo\TestBundle\Repository\PostsRepository
id:
id:
type: integer
id: true
genertor: { strategy: AUTO }
fields:
title:
type: string
length: 64
author:
type: string
length: 32
create_at:
type: integer
update_at:
type: integer
manyToOne:
category:
targetEntity: Category
inversedBy: posts
Demo\TestBundle\Entity\Category:
type: entity
table: category
repositoryClass: Demo\TestBundle\Repository\CategoryRepository
id:
id:
type: integer
id: true
genertor:
strategy: AUTO
fields:
title:
type: string
length: 16
create_at:
type: integer
update_at:
type: integer
oneToMany:
posts:
targetEntity: Posts
mappedBy: category
form表单时通过命令生成的:php app/console doctrine:generate:form DemoTestBundle:Posts
add('id')
->add('title')
->add('author')
->add('create_at')
->add('update_at')
->add('category')
;
}
/**
* @param OptionsResolverInterface $resolver
*/
public function setDefaultOptions(OptionsResolverInterface $resolver)
{
$resolver->setDefaults(array(
'data_class' => 'Demo\TestBundle\Entity\Posts'
));
}
/**
* 表单标示符, name属性
* @return string
*/
public function getName()
{
return 'posts';
}
}
大概就是这样子,不知道哪里要调还是代码错误了,希望跟路大侠指教。
例如:我想添加一篇博客,里面有一个分类,我应该有一个category_id字段,然后在添加博客的时候可以通过下拉列表选择。
疑问:
我的下拉列表中怎么才能有我添加好的分类列表呢!
posts和category的关系
#Demo\TestBundle\Entity\Posts
Demo\TestBundle\Entity\Posts:
type: entity
table: posts
repositoryClass: Demo\TestBundle\Repository\PostsRepository
id:
id:
type: integer
id: true
genertor: { strategy: AUTO }
fields:
title:
type: string
length: 64
author:
type: string
length: 32
create_at:
type: integer
update_at:
type: integer
manyToOne:
category:
targetEntity: Category
inversedBy: posts
Demo\TestBundle\Entity\Category:
type: entity
table: category
repositoryClass: Demo\TestBundle\Repository\CategoryRepository
id:
id:
type: integer
id: true
genertor:
strategy: AUTO
fields:
title:
type: string
length: 16
create_at:
type: integer
update_at:
type: integer
oneToMany:
posts:
targetEntity: Posts
mappedBy: category
form表单时通过命令生成的:php app/console doctrine:generate:form DemoTestBundle:Posts
add('id')
->add('title')
->add('author')
->add('create_at')
->add('update_at')
->add('category')
;
}
/**
* @param OptionsResolverInterface $resolver
*/
public function setDefaultOptions(OptionsResolverInterface $resolver)
{
$resolver->setDefaults(array(
'data_class' => 'Demo\TestBundle\Entity\Posts'
));
}
/**
* 表单标示符, name属性
* @return string
*/
public function getName()
{
return 'posts';
}
}
大概就是这样子,不知道哪里要调还是代码错误了,希望跟路大侠指教。
如果要用到 doctrine relationship 就用 ->add('product', 'entity' , array(...))
如果不要 doctrine relationship 就在
class PostsType extends AbstractType {
private $choices;
public function __construct( $choices)
{
$this->choices = $choices;
}
public function buildForm(FormBuilderInterface $builder, array $options)
{
....
$builder->add('category' , 'choices' , array(
'choices' => $this->choices ,
) );
}
}
在你要实例化表单的时候
public function xxxAction(){
$this->createForm( new PostsType( $this->getChoices() ) );
}
同样在Action中加入
private function getChoices()
{
//从Entitiy获取choices选项或者自己定义
return array(1 => '...' , 2 =>'....' );
}
把这个
->add('category')
改成
->add('category', 'choice')
试一下看看
->add('category', null, array('property' => 'title'));
->add('product', 'entity', array( 'class' => 'Demo\TestBundle\Entity\Category', 'property' => 'title' ))
看出错提示是说Category实体内没有实现__toString()这个方法。所以解决之道就是到Category实体里面去实现这个方法。你可以在__toString()这个方法里面返回要显示在下拉列表中的东西。比如用titile:
// file: Demo/TestBundle/Entity/Category.php
public funciton __toString() {
return $this->getTitle();
}