php的phalcon框架不能验证中文字符

直接在php中验证可以验证

$value = '电商';
preg_match('/^[a-zA-Z\x{4e00}-\x{9fa5}][a-zA-Z_\-\x{4e00}-\x{9fa5}]*$/u',$value,$m)

在phalcon的控制器的方法中就不能验证，

public function registerAction()
    {
        if($this->request->isPost())
        {
            $myValidator = new MyValidator();
            $errors = $myValidator->validateUsername($this->request->getPost('user_name'));
       }
    }

下面是调用的函数，

public function validateUsername($value)
    {
        $error = false;
        if(!preg_match('/^[a-zA-Z\x{4e00}-\x{9fa5}][a-zA-Z_\-\x{4e00}-\x{9fa5}]*$/u',$value,$m))
        {
            $error = true;
            print_r('world');
        }
        else
        {
            $pattern = '/[\x{4e00}-\x{9fa5}]/u';
            $str1    = preg_replace($pattern, '', $value, -1, $count);

            $length  = strlen($str1) + $count * 2;
            if (!($length >= 2 && $length <= 14))
            {
                $error = true;

            }

        }
        if($error)
        {
            $return = ['user_name'=>'user name is invalid2.'];
        }
        else
        {
            $return = null;
        }
        return $return;

    }

回复内容：

直接在php中验证可以验证

$value = '电商';
preg_match('/^[a-zA-Z\x{4e00}-\x{9fa5}][a-zA-Z_\-\x{4e00}-\x{9fa5}]*$/u',$value,$m)

在phalcon的控制器的方法中就不能验证，

public function registerAction()
    {
        if($this->request->isPost())
        {
            $myValidator = new MyValidator();
            $errors = $myValidator->validateUsername($this->request->getPost('user_name'));
       }
    }

下面是调用的函数，

public function validateUsername($value)
    {
        $error = false;
        if(!preg_match('/^[a-zA-Z\x{4e00}-\x{9fa5}][a-zA-Z_\-\x{4e00}-\x{9fa5}]*$/u',$value,$m))
        {
            $error = true;
            print_r('world');
        }
        else
        {
            $pattern = '/[\x{4e00}-\x{9fa5}]/u';
            $str1    = preg_replace($pattern, '', $value, -1, $count);

            $length  = strlen($str1) + $count * 2;
            if (!($length >= 2 && $length <= 14))
            {
                $error = true;

            }

        }
        if($error)
        {
            $return = ['user_name'=>'user name is invalid2.'];
        }
        else
        {
            $return = null;
        }
        return $return;

    }

http://stackoverflow.com/questions/4923319/php-check-if-the-string-has...