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JS实现浏览上传文件的代码

时间:2021-07-01 10:21:17 帮助过:15人阅读

废话不多说了,直接给大家贴代码了,具体代码如下所示:

<div style="position:relative;width:380px;">
      <iframe id="t_load" name="t_load" style="display: none"></iframe>
      <form action="" method="post" enctype="multipart/form-data" name="form1" target="t_load">
        <input type='text' name='textfield' id='textfield' style="height:22px; border:2px solid #cdcdcd; width:230px; border-radius:50px;" />
        <input type='button' value='浏览...' style="display: inline-block;
 margin-bottom: 0;
 font-size: 14px;
 border-radius: 4px;
padding: 6px 12px;
 margin: 2px 2px;
 border: 1px solid #357ebd;
 background: #1b9ad5;
 color: #fff;" />
        <input type="file" name="file1" accept="image/jpeg, image/gif" id="file1" onchange="document.getElementById('textfield').value=this.value" style="position:absolute; top:5px; right:74px; height:27px; filter:alpha(opacity:0);opacity: 0;width:300px" />
        <input type="button" name="button" onclick="mysubmit()" value="上传" style="display: inline-block;
 margin-bottom: 0;
 font-size: 14px;
 border-radius: 4px;
padding: 6px 12px;
 margin: 2px 2px;
 border: 1px solid #357ebd;
 background: #1b9ad5;
 color: #fff;">
      </form>
    </div>
    <div style="display:none;color:#6D6D72;font-size: 20px;" id="res"></div>
    <script>
      function mysubmit() {
        var a = document.getElementById("textfield").value;
        if(a == "") {
          alert("请上传文件");
          return;
        }
        document.form1.submit();
        ajaxsend();
      }
      function ajaxsend() {
        var xmlHttp;
        if(window.ActiveXObject) {
          xmlHttp = new ActiveXObject("Msxml2.XMLHTTP");
        } else {
          xmlHttp = new XMLHttpRequest();
        }
        xmlHttp.open("post", "upload", true);
        xmlHttp.onreadystatechange = function() {
          xmlHttp.readyState;
          if(xmlHttp.readyState == 4) {
            res.innerHTML = "上传成功!";
            setTimeout(function() {
              res.innerHTML = "";
            }, 2000);
          } else {
            document.getElementById("res").style.display = "inline";
          }
        }
        xmlHttp.send();
        var obj = document.getElementById('textfield');
        obj.outerHTML = obj.outerHTML;
      }
    </script>

总结

以上所述是小编给大家介绍的JS实现浏览上传文件的代码,希望对大家有所帮助,如果大家有任何疑问请给我留言,小编会及时回复大家的。在此也非常感谢大家对脚本之家网站的支持!

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