时间：2021-07-01 10:21:17 帮助过：5人阅读
本文实例讲述了JS实现图片平面旋转的方法。分享给大家供大家参考，具体如下：
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>图片旋转</title>
<style type="text/css" >
#div1{ position:relative;height:800px; border:1px solid red;}
#div1 img{ position:absolute;}
</style>
</head>
<body >
<div id="div1" >
<img src="//www.gxlcms.com/images/logo.gif" />
<img src="//www.gxlcms.com/images/logo.gif" />
<img src="//www.gxlcms.com/images/logo.gif" />
<img src="//www.gxlcms.com/images/logo.gif" />
<img src="//www.gxlcms.com/images/logo.gif" />
<img src="//www.gxlcms.com/images/logo.gif" />
</div>
<script type="text/javascript" >
var centerx = 400; //圆心X
var centery = 300; //圆心Y
var r = 300; //半径
var oimages = document.getElementById("div1").getElementsByTagName("IMG"); //图片集合
var cnt = oimages.length; //图片数
var da = 360 / cnt; //图片间隔角度
var a0 = 0; //已旋转角度
var timer;
for (var i = 0; i < cnt; i++) {
oimages[i].onmouseover = stop;
oimages[i].onmouseout = start;
}
function posimgs() {
for (var i = 0; i < cnt; i++) {
oimages[i].style.left = centerx + r * Math.cos((da * i + a0) / 180 * Math.PI) + "px";
oimages[i].style.top = centery + r * Math.sin((da * i + a0) / 180 * Math.PI) + "px";
}
}
// posimgs();
function start() {
timer = window.setInterval("posimgs();a0++;", 100);
}
function stop() {
window.clearInterval(timer);
}
start();
</script>
</body>
</html>
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希望本文所述对大家JavaScript程序设计有所帮助。