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JS获取URL中的参数数据

时间:2021-07-01 10:21:17 帮助过:25人阅读

代码如下:
function getParam(paramName) {
    paramValue = "";
    isFound = false;
    if (this.location.search.indexOf("?") == 0 && this.location.search.indexOf("=") > 1) {
        arrSource = unescape(this.location.search).substring(1, this.location.search.length).split("&");
        i = 0;
        while (i < arrSource.length && !isFound) {
            if (arrSource[i].indexOf("=") > 0) {
                if (arrSource[i].split("=")[0].toLowerCase() == paramName.toLowerCase()) {
                    paramValue = arrSource[i].split("=")[1];
                    isFound = true;
                }
            }
            i++;
        }
    }
    return paramValue;
}

如://www.gxlcms.com/UserQuery.aspx?id=202
getParam("id")为202

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