当前位置:Gxlcms > JavaScript > ajax怎么实现远程通信功能

ajax怎么实现远程通信功能

时间:2021-07-01 10:21:17 帮助过:3人阅读

这次给大家带来ajax怎么实现远程通信功能,ajax实现远程通信功能的注意事项有哪些,下面就是实战案例,一起来看一下。

本文实例为大家分享了ajax实现远程通信,供大家参考,具体内容如下

第一个文件:html

<!DOCTYPE html>
<html lang="en">
<head>
  <meta charset="UTF-8">
  <title>ajax解决跨域问题</title>
  <script src="jquery-3.0.0.min.js" type="text/javascript"></script>
</head>
<body>
<script>
  $.ajax({
    type:"POST",
    url:"postDemo.php",
    data:{
      "url":"http://192.168.4.101:90/PHPStudy4/server.php",
      "username":"admin",
      "password":"admin",
    },success:function(data){
      var result=eval("("+data+")");
      console.log(result);
    }
  })
</script>
</body>
</html>

第二个文件:服务器端处理数据

<?php
/**
 * Created by PhpStorm.
 * User: Administrator
 * Date: 2016-7-21
 * Time: 10:12
 */
if ($_SERVER["REQUEST_METHOD"] == "POST") {
//  echo json_encode(array("111"=>"112"));
  if (isset($_POST["url"]) && isset($_POST["username"]) && isset($_POST["password"])) {
    $result = postDemo($_POST["url"], array("username" => $_POST["username"], "password" => $_POST["password"]));
    echo $result;
  } else {
    echo json_encode(array("msg2" => "!!!!!!!!!!!!!!!!!!!!!error!!!!!2"));
  }
} else {
  echo json_encode(array("msg" => "error!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!"));
}
function postDemo($url, $data)
{
  $query = http_build_query($data);
  $options = array(
    "http" => array(
      "header" => "Content-type: application/x-www-form-urlencoded\r\n" .
        "Content-length:" . strlen($query) . "\r\n" .
        "User-Agent:MyAgent/1.0/r/n",
      "method" => "POST",
      "content" => $query
    )
  );
  $content = stream_context_create($options);
  $result = file_get_contents($url, false, $content);
  return $result;
}
//echo postDemo("http://192.168.4.101:90/PHPStudy4/server.php",array("username"=>"admin","password"=>"admin"));

相信看了本文案例你已经掌握了方法,更多精彩请关注Gxl网其它相关文章!

推荐阅读:

ajax提交数据到后台数据库后实现用户注册

Ajax结合php怎么实现二级联动

以上就是ajax怎么实现远程通信功能的详细内容,更多请关注Gxl网其它相关文章!

人气教程排行