时间:2021-07-01 10:21:17 帮助过:74人阅读
本文我们主要和大家分享JS实现根据出生日期得到年龄方法,希望能帮助到大家。
JavaScript//JS根据出生日期 得到年龄 //参数strBirthday已经是正确格式的2017-12-12这样的日期字符串 function jsGetAge(strBirthday) { var returnAge; var strBirthdayArr=strBirthday.split("-"); var birthYear = strBirthdayArr[0]; var birthMonth = strBirthdayArr[1]; var birthDay = strBirthdayArr[2]; var d = new Date(); var nowYear = d.getYear(); var nowMonth = d.getMonth() + 1; var nowDay = d.getDate(); if(nowYear == birthYear) { returnAge = 0;//同年 则为0岁 } else { var ageDiff = nowYear - birthYear ; //年之差 if(ageDiff > 0) { if(nowMonth == birthMonth) { var dayDiff = nowDay - birthDay;//日之差 if(dayDiff < 0) { returnAge = ageDiff - 1; } else { returnAge = ageDiff ; } } else { var monthDiff = nowMonth - birthMonth;//月之差 if(monthDiff < 0) { returnAge = ageDiff - 1; } else { returnAge = ageDiff ; } } } else { returnAge = -1;//返回-1 表示出生日期输入错误 晚于今天 } } return returnAge;//返回周岁年龄 }
JavaScript//JS根据出生日期 得到年龄 //参数strBirthday已经是正确格式的2017-12-12这样的日期字符串 function jsGetAge(strBirthday) { var returnAge; var strBirthdayArr=strBirthday.split("-"); var birthYear = strBirthdayArr[0]; var birthMonth = strBirthdayArr[1]; var birthDay = strBirthdayArr[2]; var d = new Date(); var nowYear = d.getYear(); var nowMonth = d.getMonth() + 1; var nowDay = d.getDate(); if(nowYear == birthYear) { returnAge = 0;//同年 则为0岁 } else { var ageDiff = nowYear - birthYear ; //年之差 if(ageDiff > 0) { if(nowMonth == birthMonth) { var dayDiff = nowDay - birthDay;//日之差 if(dayDiff < 0) { returnAge = ageDiff - 1; } else { returnAge = ageDiff ; } } else { var monthDiff = nowMonth - birthMonth;//月之差 if(monthDiff < 0) { returnAge = ageDiff - 1; } else { returnAge = ageDiff ; } } } else { returnAge = -1;//返回-1 表示出生日期输入错误 晚于今天 } } return returnAge;//返回周岁年龄 }
相关推荐:
MYSQL 日期函数总结
JS实现两个日期比较相差多少天的案例
mysql如何自动获取时间日期的实例详解
以上就是JS实现根据出生日期得到年龄方法的详细内容,更多请关注Gxl网其它相关文章!