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JavaScript读URL参数增强改进版版_javascript技巧

时间：2021-07-01 10:21:17 帮助过：3人阅读

function getUrlArg(seekArg) 
{ 
var url= location.href;

//先用正则把问号和井号之间的参数部分分离出来，如从 http://www.gxlcms.com/testjs.htm?p=1&t=1&u=1#test 中分出 p=1&t=1&u=1 
if (reMatch = url.match(/\?([^#]+)#?/)) 
{ 
var querystring = reMatch[1]; 
//用正则按 & 或 = 拆分到数组里，args 数组中依次是变量名和变量值，如p,1,t,2,u,24 
var args = querystring.split(/&|=/); 
//必须把 arg 声明成对象，如果只写 var arg; 后面赋值时会报错说 arg 这个变量未定义 
var arg={}; 
for(i=0;i<br/><INPUT onclick="runEx('runcode74320')" type="button" value="运行代码"/> <INPUT onclick="doCopy('runcode74320')" type="button" value=""/> <INPUT onclick="doSave(runcode74320)" type="button" value="保存代码"/>[Ctrl+A 全选 注:如需引入外部Js需刷新才能执行]</div>                    </div>

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