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js计算两个时间之间天数差的实例代码_javascript技巧

时间:2021-07-01 10:21:17 帮助过:9人阅读

代码如下:

//判断是否为闰年
function isLeapYear(year){
if(year % 4 == 0 && ((year % 100 != 0) || (year % 400 == 0)))
{
return true;
}
return false;
}
//判断前后两个日期
function validatePeriod(fyear,fmonth,fday,byear,bmonth,bday){
if(fyear < byear){
return true;
}else if(fyear == byear){
if(fmonth < bmonth){
return true;
} else if (fmonth == bmonth){
if(fday <= bday){
return true;
}else {
return false;
}
} else {
return false;
}
}else {
return false;
}
}
//计算两个日期的差值
function dateDiff(d1,d2){
var disNum=compareDate(d1,d2);
return disNum;
}
function compareDate(date1,date2)
{
var regexp=/^(\d{1,4})[-|\.]{1}(\d{1,2})[-|\.]{1}(\d{1,2})$/;
var monthDays=[0,3,0,1,0,1,0,0,1,0,0,1];
regexp.test(date1);
var date1Year=RegExp.$1;
var date1Month=RegExp.$2;
var date1Day=RegExp.$3;

regexp.test(date2);
var date2Year=RegExp.$1;
var date2Month=RegExp.$2;
var date2Day=RegExp.$3;

if(validatePeriod(date1Year,date1Month,date1Day,date2Year,date2Month,date2Day)){
firstDate=new Date(date1Year,date1Month,date1Day);
secondDate=new Date(date2Year,date2Month,date2Day);

result=Math.floor((secondDate.getTime()-firstDate.getTime())/(1000*3600*24));
for(j=date1Year;j<=date2Year;j++){
if(isLeapYear(j)){
monthDays[1]=2;
}else{
monthDays[1]=3;
}
for(i=date1Month-1;i result=result-monthDays[i];
}
}
return result;
}else{
alert('对不起第一个时间必须小于第二个时间,谢谢!');
exit;
}
}


调用该函数传递两个时间值:2013-01-19 2013-12-19

days = dateDiff(d1,d2);

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