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测试JavaScript字符串处理性能的代码

时间:2021-07-01 10:21:17 帮助过:5人阅读

代码如下:

var oldtime = new Date().getTime();
var str = [];
for(i=0;i<100000;i++)
{
str.push('abcabcabcabcabcabcabcabcabcabcabcabc');
}
var newtime = new Date().getTime();
var joinTime = (newtime - oldtime);

var oldtime = new Date().getTime();
var str='';
for(i=0;i<100000;i++)
{
str += 'abcabcabcabcabcabcabcabcabcabcabcabc';
}
var newtime = new Date().getTime();
var concatTime = (newtime - oldtime);

alert("join / concat: " + (joinTime * 1.0 / concatTime));

注:循环次数必须足够大。

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